Sgtest

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<math> \pi= \frac{3}{4} \sqrt{3}+24 \int_0^{1/4}{\sqrt{x-x^2}dx} </math>

<math> \pi= \frac{3}{4} \sqrt{3}+24 \int_0^{1/4}{\sqrt{x-x^2}dx} </math>


<math> \pi= \frac{3}{4} \sqrt{3}+24 \int_0^{1/4}{\sqrt{x-x^3}dx} </math>